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Every latin hypercube of order 5 has transversals Full article

Journal Journal of Combinatorial Designs
ISSN: 1063-8539
Output data Year: 2024, Volume: 32, Number: 11, Pages: 679-699 Pages count : 21 DOI: 10.1002/jcd.21954
Tags latin hypercube, latin square, nonextendible latin cuboid, permanent of multidimensional matrix, transversal
Authors Perezhogin Alexey L. 1 , Potapov Vladimir N. 2 , Vladimirov Sergey Yu. 3
Affiliations
1 Sobolev Institute of Mathematics Novosibirsk Russia
2 Sabanci University, Faculty of Engineering and Natural Sciences Istanbul Turkey
3 Novosibirsk State University, Faculty of Information Technologies Novosibirsk Russia

Funding (1)

1 Sobolev Institute of Mathematics FWNF-2022-0017

Abstract: We prove that for all n > 1 every latin n‐dimensional cube of order 5 has transversals. We find all 123 paratopy classes of layer‐latin cubes of order 5 with no transversals. For each ≥ n 3and ≥ q q q ⋯ latin square of order q is aq q q 3weconstruct a (2 − 2) × × × latin n‐dimensional cuboid of order q with no transversals. Moreover, we find all paratopy classes of nonextendible and noncompletable latin cuboids of order 5.
Cite: Perezhogin A.L. , Potapov V.N. , Vladimirov S.Y.
Every latin hypercube of order 5 has transversals
Journal of Combinatorial Designs. 2024. V.32. N11. P.679-699. DOI: 10.1002/jcd.21954 WOS Scopus РИНЦ OpenAlex
Dates:
Submitted: Nov 25, 2023
Accepted: Jul 15, 2024
Published print: Jul 30, 2024
Published online: Jul 30, 2024
Identifiers:
Web of science: WOS:001281441800001
Scopus: 2-s2.0-85200028211
Elibrary: 69039729
OpenAlex: W4401131688
Citing:
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OpenAlex 1
Scopus 1
Web of science 1
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